A mistake two wrong wrong wrong wrong even three assumptions are wrong
Aware of. An example is to analyze, for example a reference to the students that: (ab + ca) ≤ (& + c) (b + d) the wrong card: set port =, fina, b = n Lu, c = aim, d = aim . The mouth + c2 = 1. b + d2 = 1. '. (Qu +) = (slnasinfl + ∞ so ∞ p) = (x362 (-f1) ~ l ,.'.( West + resistance) ≤ (mouth ten c2) (b + d). Analysis: b; grapes np, f = oo6a, d = o ∞ 'after so Ⅱ and c, b and d into the sine and cosine of an angle, a square and 1 additional conditions, so that loss of generality. the right card Method: (song +) = port b + c. d +2 abcd ≤ Ⅱ b + cd + a2d + c2b = (Ⅱ 2 + c) (6 + d) Example 2 Let S ¨ L respectively arithmetic progression iane, {j's in the preceding paragraph and, if for all natural number n,; Li 7n +2. wrong solution: .= Li 7n +2,
diesel store paris, it can set s = (7n +2) k. = (3 + 4) the amount (volume ≠ 0) , Tony 4lD = Sjo-s9 = (7 × 10 +2) k a (7 × 9 +2) k = 7k, blD = T10 a T9 = (3 × 10 +4) (3 × 9 +4) = 3k .. a10 thirty-one bl0-3 analysis: At first glance the process seems perfect answer, but this is really a wrong answer to see the following discussion, the error due to self-evident. arithmetic sequence in the preceding paragraph and the formula S = coral ten divisions ( a 1) d, d ≠ 0 in the tolerance conditions on the quadratic function, and the constant term is zero,
mbt cipő, second function, and thus the result of course is wrong .2001 No. 8 iF_ really Solution: Let s = (7n +2) kn, 1 = (3n +4) h (k4-0, k is constant), this imitation is not too irresolute =. The results for this question, students can choose from the following simple solution to get another test another solution: = 2alo =(。。+)( 61 + big) a Sl9: !!: a 135TI93 × 19 +461 3 are known to down a geometric series plot of the first four of 16, second, third, and two of 5, find the common ratio of this geometric series by ① too a = ± 2, in order ② generations have 2q ± 5q +2 = 0 - '· q = ± {or q = + -2. Therefore, the original series of common ratio for the q2 = {or 4 analysis: The above solution, using set out the geometric symmetry of the first four columns, unique, simple operation,
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ed hardy canada, but according to the above this limit, such a number of the first four were located, One,, q,
mulberry bags uk, rd4 = 16 eleven from known {-a --- + aq = 5, = or = ll get the solution of the original series of common ratio for q2 =--- 33 + l_5. ~ / TI To sum up, the original series of common ratio is 4 or {or;! take another solution: Let the geometric series of the first four were a, aq, aq, aq, then from the had known there {aq This sour know: is the wrong solution is
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