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Parallelogram associated with the mathematical ideas


CD, / B = / D,true religion outlet, confirmation: quadrilateral ABCD is a parallelogram. Analysis: To prove that quadrilateral ABCD is a parallelogram, as AB / / CD, so long as to prove that AB = CDIO available. This line will be available for auxiliary parallelogram into triangles to solve problems, then you can link Ac. Proof: link AC. Because AB ∥ CD, so c: DCA. And B = D, AC = CA, so △ ABC △ CDA, IOAB = CD. . 4 -----] D /,,/. B/_1 and AB ∥ CD, so the quadrilateral ABCD is a parallelogram. Second, the classification of ideas in zz7ABCD in Example 2,tory burch outlet, AE split side BC at point D AC E, if the point E points 3 and 4 BC in two parts, the perimeter is ~ ABCD is (). A. 20B. 22C. 20 and 22D. 20 or 22 analysis: requirements ~: TABCD the perimeter, you can first draw the graph in Figure 2, according to conditions AE potato 2OO8. 1-2 split BAD side BC at point of delivery E, E points as points 3 and 4 BC in two parts, so the two cases discussed. Solution: Figure 2, in tzYTABCD, because AE split side BC at point D AC E, so / _AEB = BEAD = BAE ~ [IBA = BE. Point E in Figure 2 points 3 and 4 BC in two parts, divided into two cases: ① If the boat = 3,. ~ JJEC = 4, so AB = 3, P, IJIS3ABCD circumference of 20; ② If BE = 4,######## oakley sunglasses, then the EC: 3, so AB = 4, ~ IlE3ABCD the perimeter is 22. That tzYTABCD circumference of 20 or 22. Select D. Third, the overall ideology Example 3 in Figure 3, in AMBN in, BM = 6, points A, C, D, respectively, in MB, BN, NM, the quadrilateral ABCD is a parallelogram, / _NDC = / _MDA, tzYTABCD the perimeter is (). A. 24.18C. 16D. 12 Analysis: requirements tzYTABCD the perimeter, if obtained AB + AD, you can solve a whole. Solution: the quadrilateral ABCD is a parallelogram shows / _NDC = DMA, and NDC = MDA. Therefore, MDA = DMA, ~ [IAD = AM. So AB + AD = AB + AM = BM. And BM = 6, tzYTABCD circumference = 2x6 = 12. Select D. Fourth, the equation thinking of Example 4 in Figure 4, in the tzZ3ABCD, AE on BC, AF_LCD, pedal, respectively E, F,radii shoes sale, if AE: 4, AF = 6, tzYTABCD the perimeter is 40, then the area S is equal to tzYTABCD How many? Solution: If set AB = x, then the BC 20 a. According to the parallelogram area formula, 4 (20 a) = 6x, solve for x = 8,GHD Glätteisen günstig, ~ OAB = 8. S = 8x6 = 48. Circle MAB Figure 3 / / F Figure 42008.1-2
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