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chanel sunglasses 2011
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Reprinted from alumni of the user at 11:10 on 5 March 2010 read (loading. ..) Comments (0) Category: turn 1. ten by ten:
formulas: the head by head,
sunglasses 2011, tail plus tail, tail by tail.
Example: 12 × 14 =?
solution: 1 × 1 = 1
2 +4 = 6
2 × 4 = 8
12 × 14 = 168
Note: a bit multiply, not use the 0 digit placeholder.
2. head the same, complementary tail (tail add up to 10):
formulas: a first add 1 to the head by head,
dior sunglasses 2011, tail by tail.
Example: 23 × 27 =?
Solution: 2 +1 = 3
2 × 3 = 6
3 × 7 = 21
23 × 27 = 621
Note: a bit multiply,
sunglasses hut, not use the 0 digit placeholder.
3. complementary first multiplier, the same as the other multiplier:
formulas: a first add 1 to the head by head, tail by tail.
Example: 37 × 44 =?
solution: 3 +1 = 4
4 × 4 = 16
7 × 4 = 28
37 × 44 = 1628
Note: a bit multiply,
oakley sunglasses 2011, not use the 0 digit placeholder.
4. dozens of dozens of one by one:
formulas: head by head, head plus head, tail by tail.
Example: 21 × 41 =?
solutions: 2 × 4 = 8
2 +4 = 6
1 × 1 = 1
21 × 41 = 861
5.11 by any number:
formulas: sum of fixed fate, and the middle of the drop-down.
Example: 11 × 23125 =?
Solution: 2 +3 = 5
3 +1 = 4
1 +2 = 3
2 +5 = 7
2 and 5, respectively, in the end to end
11 × 23125 = 254375
Note: and over ten to get into one.
6. dozen by any number:
formulas: the whereabouts of the second movement is not the first multiplier, the first digit multiplied by the factor The second factor behind each number, plus the next digit,
dior sunglasses, again missing.
Example: 13 × 326 =?
solution: 13 bits is 3
3 × 3 +2 = 11
3 × 2 +6 = 12
3 × 6 = 18
13 × 326 = 4238
Note: and over ten to get into one.